2105.08402
Differentiable solutions of an equation with product of iterates
Chaitanya Gopalakrishna
correctmedium confidence
- Category
- Not specified
- Journal tier
- Strong Field
- Processed
- Sep 28, 2025, 12:56 AM
- arXiv Links
- Abstract ↗PDF ↗
Audit review
The paper proves existence and uniqueness of differentiable solutions to the product-of-iterates equation on R+ by conjugating to a polynomial-like equation on R, defining L_f(x)=∑_{k=1}^n λ_k f^{k-1}(x), and applying a Banach contraction to T(f)=L_f^{-1}∘F with careful estimates for the constants K0,…,K6 and M' = M*/(λ1−K0 M^2) under λ1>K0 M^2 and K<1. The candidate solution reproduces the same strategy in logarithmic variables (φ = log g∘exp, H = log G∘exp), with F_φ mirroring L_f and the fixed-point map S~=F_φ^{-1}∘H. The contraction bounds and the choice M' = M*/(λ1−K0 M^2) agree with the paper’s Theorem 3.1 and its proof, including the two-part Lipschitz estimates analogous to (3.4)–(3.5). Minor differences are notational (e.g., K3 vs. K'_3) and organizational (working first on I then extending), but the mathematical content and logic are essentially the same as the paper’s proof. See the theorem statement and proof details and the contraction estimates in Theorem 3.1 and Lemma 2.12 in the PDF , the reduction via conjugation and class definitions , and the contraction inequalities (3.4)–(3.5) .
Referee report (LaTeX)
\textbf{Recommendation:} minor revisions
\textbf{Journal Tier:} strong field
\textbf{Justification:}
The paper’s method—conjugation to a polynomial-like equation on R, followed by a contraction argument—works cleanly, with careful tracking of constants and hypotheses. The existence and uniqueness result addresses a gap for differentiable solutions on non-compact domains. A few clarifications on constants and the role of the normalization ∑λk=1 would enhance readability, but the core mathematics is correct and well structured.