2012.13621
Solvable systems of two coupled first-order ODEs with homogeneous cubic polynomial right-hand sides
Francesco Calogero, Farrin Payandeh
correctmedium confidence
- Category
- Not specified
- Journal tier
- Specialist/Solid
- Processed
- Sep 28, 2025, 12:55 AM
- arXiv Links
- Abstract ↗PDF ↗
Audit review
The paper’s Proposition 1-1 solves the cubic planar system by an invertible linear change (y = a1 x1 + a2 x2, w = b1 x1 + b2 x2) that yields ẏ = y^3 and ẇ = w^3 + γ1 y w^2 + γ2 y^2 w + γ3 y^3, then sets u = w/y to separate and integrate, obtaining the implicit product law for u(t) together with the explicit y(t) = y(0)[1 − 2 y(0)^2 t]^{-1/2} (see formulas (6)–(12), (14)–(17) in the paper). The candidate solution reproduces the same steps: it verifies the linear identities implied by (6) to get ẏ = y^3 and the stated ẇ, reduces to u, performs the same partial-fraction integration using the λ-constraints, and reconstructs x via x = M^{-1}(y,w) (matching (8)–(10) and (16d), (17)). Minor caveats (c ≠ 0, y(0) ≠ 0 for u(0), and handling repeated roots of the cubic) are tacit in both. Overall, the argument and details coincide closely with the paper’s proof sketch of Proposition 1-1, and the solution is correct. Key loci in the paper: statement and formulas (6)–(10) and c ≠ 0 in (7e) , explicit y(t) and the product law for u(t) in (9), (10) , the u-ODE and verification in (16d), (17) , and λ-conditions (12a,b) .
Referee report (LaTeX)
\textbf{Recommendation:} minor revisions
\textbf{Journal Tier:} specialist/solid
\textbf{Justification:}
The paper precisely characterizes and solves a nontrivial class of cubic planar systems. The argument is correct and the construction is explicit. The inversion and constraint analysis enhance practical utility. Minor clarifications on edge cases (initial data with y(0)=0, repeated roots in the cubic for u, branch choices) would make the presentation even clearer.